2+4y^=y^+14

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Solution for 2+4y^=y^+14 equation: 



2+4y^=y^+14

We move all terms to the left:

2+4y^-(y^+14)=0

We add all the numbers together, and all the variables

4y-(y^+14)+2=0

We get rid of parentheses

4y-y^-14+2=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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